[OE-core] [PATCH] image_types: add IMAGE_ROOTFS_ALIGNMENT

[Ken Werner]

On 03/02/2012 01:44 AM, Saul Wold wrote:
> On 03/01/2012 12:55 PM, Ken Werner wrote:
>> Introduce a new variable called IMAGE_ROOTFS_ALIGNMENT that allows to
>> control
>> the aligment of the size of the rootfs. Its default value is set to
>> 1KiB so
>> that the existing behaviour is not changed. In case the SD card
>> emulation of
>> a QEMU system emulator gets used you may set the alignment to 2MiB.
>> ---
>> meta/classes/image_types.bbclass | 12 +++++++++++-
>> 1 files changed, 11 insertions(+), 1 deletions(-)
>>
>> diff --git a/meta/classes/image_types.bbclass
>> b/meta/classes/image_types.bbclass
>> index f756c39..314d6d1 100644
>> --- a/meta/classes/image_types.bbclass
>> +++ b/meta/classes/image_types.bbclass
>> @@ -55,9 +55,19 @@ def get_imagecmds(d):
>> cmds += "\n" + localdata.getVar("runimagecmd", True)
>> return cmds
>>
>> +# The default aligment of the size of the rootfs is set to 1KiB. In case
>> +# you're using the SD card emulation of a QEMU system simulator you may
>> +# set this value to 2048 (2MiB alignment).
>> +IMAGE_ROOTFS_ALIGNMENT ?= "1"
>> +
>> runimagecmd () {
>> # Image generation code for image type ${type}
>> - ROOTFS_SIZE=`du -ks ${IMAGE_ROOTFS}|awk '{base_size = ($1 *
>> ${IMAGE_OVERHEAD_FACTOR}); OFMT = "%.0f" ; print ((base_size>
>> ${IMAGE_ROOTFS_SIZE} ? base_size : ${IMAGE_ROOTFS_SIZE}) +
>> ${IMAGE_ROOTFS_EXTRA_SPACE}) }'`
>> + # The base_size gets calculated:
>> + # - initial size determined by `du -ks` of the IMAGE_ROOTFS
>> + # - then multiplied by the IMAGE_OVERHEAD_FACTOR
>> + # - then rounded up to IMAGE_ROOTFS_ALIGNMENT
>> + # - finally tested against IMAGE_ROOTFS_SIZE
>> + ROOTFS_SIZE=`du -ks ${IMAGE_ROOTFS}|awk '{base_size = $1 *
>> ${IMAGE_OVERHEAD_FACTOR} + ${IMAGE_ROOTFS_ALIGNMENT} - 1; base_size -=
>> base_size % ${IMAGE_ROOTFS_ALIGNMENT}; print ((base_size>
>> ${IMAGE_ROOTFS_SIZE} ? base_size : ${IMAGE_ROOTFS_SIZE}) +
>> ${IMAGE_ROOTFS_EXTRA_SPACE}) }'`
>> ${cmd}
> Is there a reason you removed the OFMT from this line?

Hi,

Thanks for reviewing!
I'm not too much into awk but I thought the fraction part of the result 
from the modulo operation equals the fraction part of the initial 
base_size. Since we subtract each other only the integer part remains.

Regards,
Ken

> Sau!
>> # Now create the needed compressed versions
>> cd ${DEPLOY_DIR_IMAGE}/