[oe] [meta-oe][PATCH] socorro-syms: Add support for local repositories
Daniel Markus
daniel.markus at leica-geosystems.com
Thu Mar 26 08:20:06 UTC 2015
This socorro-syms functionality tries to extract the host name out of the source
code repository origin. This causes problems when the origin is a local
repository.
The solution is to look for the origin in two steps. If the origin in the first
step is a local directory we assume it is a temporary download repository. In
the second step we look for the origin to that download repository and if that
also redirects to a local repository, we provide the absolute path instead of a
Socorro repository link.
Signed-off-by: Daniel Markus <daniel.markus at leica-geosystems.com>
---
meta-oe/classes/socorro-syms.bbclass | 14 +++++++++++++-
1 file changed, 13 insertions(+), 1 deletion(-)
diff --git a/meta-oe/classes/socorro-syms.bbclass b/meta-oe/classes/socorro-syms.bbclass
index c272952..0312031 100644
--- a/meta-oe/classes/socorro-syms.bbclass
+++ b/meta-oe/classes/socorro-syms.bbclass
@@ -108,6 +108,12 @@ def run_command(command, directory):
return output.rstrip()
+def is_local_url(url):
+
+ return \
+ url.startswith("file:") or url.startswith("/") or url.startswith("./")
+
+
def git_repository_path(source_file_path):
import re
@@ -125,12 +131,18 @@ def git_repository_path(source_file_path):
# The URL could be a local download directory. If so, get the URL again
# using the local directory's config file.
- if os.path.isdir(source_long_url):
+ if is_local_url(source_long_url):
git_config_file = os.path.join(source_long_url, "config")
source_long_url = run_command(
"git config --file %s --get remote.origin.url" % git_config_file,
source_file_dir)
+ # If also the download directory redirects to a local git directory,
+ # then we're probably using source code from a local debug branch which
+ # won't be accessible by Socorro.
+ if is_local_url(source_long_url):
+ return None
+
# The URL can have several formats. A full list can be found using
# git help clone. Extract the server part with a regex.
url_match = re.search(".*(://|@)([^:/]*).*", source_long_url)
--
1.9.1
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